Max

Maximum value

Median

The median is the 'middle' value from a set of values



Part equation segment

Example

"You can solve it using divide and conquer approach find a random element in between the minimum and maximum check if it s median if the median is lower or higher than the median and reduce the problem to a smaller size only on a subrange of the array"

from question  

Find the median in an unsorted read-only array

"So the t 7n 10 is the part of continuing the equation with the max segment of numbers that is larger smaller than the median of medians.."

from question  

Median of median algorithm recurrence relation

Others

Example

This is just binary search by median value compare with example code stops iterations when borders collide when we call self.findmedianinlargefile numbers k max result+1 guess right because our guess was too small and median value is bigger than quessed value

from question  

Finding Median in Large Integer File of Integers

Therefore the max number of elements you could have that are greater than or less than the median of median is 3 10 + 2 10 + 2 10 7 10

from question  

Median of median algorithm recurrence relation

So after calculating median of first k elements delete the first element directly from heap min or max according to whether it is greater or less than median using pointers and then use heapify at that position

from question  

Median of large amount of numbers for each sets of given size

Back to Home
Data comes from Stack Exchange with CC-BY-SA-4.0