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Anything named - objects, variables, classes..


In computer programming, shadowing occurs when a variable declared within a certain scope (decision block, method or inner class) has the same name as a variable declared in an outer scope. This can lead to confusion, as it may be unclear which variable subsequent uses of the shadowed variable name refer to, which depends on the name resolution rules of the language.



Not using the same named is a more common practice to avoid confusion and shadowing

from question  

Java - when "this" is the only way to go?

Shadowing is more general term it is applicable outside the ruby world too;shadowing means that the named you use in an outer scope - is shadowed by local one therefore makes in non accessible and confusing

from question  

What does "shadowing" mean in Ruby?

His effect is called shadowing;this effect means that all variables with named value are always there but if you lookup the named one is found earlier thus making the other invisible shadowed

from question  

Clarification of JavaScript variable scope

When you re not worrying about shadowing this is more flexible if the named of the object changes

from question  

Whats the difference between using 'this' and the object name for reference inside the object?

In scheme you are making a local binding shadowing whatever is higher with let;since + and are just variables that just happen to evaluate to procedures you are just giving old procedures other variable named

from question  

Why does Lisp allow replacement of math operators in let?

I believe the reasoning behind it is that it allows the parameters to be named nicer by preventing shadowing of member variables

from question  

Programming style from "Game Coding Complete"

From the book note that shadowing a named does not alter or destroy the value it was bound to and the value will continue to exist until it goes out of scope even if it is no longer accessible by any means the previous value is not more accessible after shadowing and it will be destroyed at the end of the scope not when the variable is shadowed

from question  

Variable shadowing in the same scope in Rust?

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